54 Gradient Descent Algorithm in R
Cong Chen
54.1 Motivation
The Gradient Descent Algorithm is a popular algorithm in optimization. However, I seldom see people apply the algorithm by R, so I try to apply the Gradient Descent Algorithm to a simple optimization problem by R. And I also use three different step size rules when applying Gradient Descent Algorithm and drawing the contour map to give a more comprehensive understanding about the difference between these methods.
Through the project, I understood the principle of the algorithm more clearly and was skilled in applying the algorithm. And I also realized how important choosing initial values are. Maybe the next time, I will try other different step size rules.
54.2 Gradient Descent Algorithm
Gradient Descent Algorithm is an algorithm used widely in optimization. For a simple optimization problem:
\[ \min_{x\in X}f(x) \] where \(X\) is the domain of variable \(x\), the algorithm’s specific steps are shown below:
Choose the initial value of \(x\) called \(x^{(0)}\).
Choose the stopping condition value of the algorithm \(\varepsilon\).
Select a specific step size rule to determine \(\alpha^{(t)}\) for \(t=0,1,...\).
For \(t=0,1,...\), update: \[ x^{(t+1)}=x^{(t)}-\alpha^{(t)}\nabla f(x^{(t)}) \]
If \(\lVert x^{(t+1)}-x^{(t)} \rVert\leq \varepsilon\), stop the algorithm.
54.3 Three common step size rules
There are three common step size rules:
Fixed: \(\alpha^{(t)}\) is a constant.
Exact line search
Backtracking line search
Exact line search method tries to find the best \(\alpha^{(t)}\) in each step \(t\), that is: \[ \alpha^{(t)}=\arg\min_{\alpha} (x^{(t)}-\alpha\nabla f(x^{(t)})) \]
Backtracking line search method tries to reduce the step size as the iteration \(t\) increases.
54.4 A simple problem
Apply these three methods to a simple optimization problem to find its optimal solution. And also, compare the difference between these three methods based on the results.
A simple optimization problem: \[ \min_{x=(x_1,x_2)} f(x)\\ f(x)=\frac{10x_1^2+x_2^2}{2} \]
# function f(x)
f<-function(x){
return((10*x[1]^2+x[2]^2)/2)
}
# gradient of f(x)
grad<-function(x){
return(c(10*x[1],x[2]))
}
In all three methods, the search begins at the point \(x^{(0)}=(1.5,-1.5)\).
54.4.1 Fixed step size
fixstep<-function(x0, grad, tol = 1e-6, alpha = 0.01, max_iteration = 1000){
k = 1
xf = x0
xl = xf - alpha * grad(xf)
x = c(x0,xl)
while (sqrt(sum((xl - xf)^2)) > tol && k < max_iteration){
xf = xl
xl = xf - alpha * grad(xf)
k = k + 1
x = c(x, xl)
}
return(list(iteration = k - 1,
x1 = x[seq(1, 2 * k - 1, 2)],
x2 = x[seq(2, 2 * k, 2)]))
}
try three different fixed step size to observe their different processes:
Small: \(\alpha = 0.01\).
Medium: \(\alpha = 0.1\).
Large: \(\alpha = 0.7\).
# implement the method
step1 = fixstep(c(1.5, -1.5), grad, alpha = 0.01)
step2 = fixstep(c(1.5, -1.5), grad, alpha = 0.1)
step3 = fixstep(c(1.5, -1.5), grad, alpha = 0.7, max_iteration = 50)
z = matrix(0, 100, 100)
x1 = seq(-1.5, 1.5, length = 100)
x2 = seq(-1.5, 1.5, length = 100)
# store function value for every grid point
for(i in 1:100){
for(j in 1:100){
z[i,j] = f(c(x1[i],x2[j]))
}
}
# plot contour map
contour(x1, x2, z, nlevels=20)
for(i in 1:step1$iteration){
segments(step1$x1[i],step1$x2[i],step1$x1[i+1],step1$x2[i+1],lty=2,col='red')
}
for(i in 1:step2$iteration){
segments(step2$x1[i],step2$x2[i],step2$x1[i+1],step2$x2[i+1],lty=2,col='blue')
}
for(i in 1:step3$iteration){
segments(step3$x1[i],step3$x2[i],step3$x1[i+1],step3$x2[i+1],lty=2,col='green')
}
The small \(\alpha\) (red line in the graph) takes more iteration to find the optimal solution, while the large \(\alpha\) (green line in the graph) leads huge fluctuations in search, which makes it difficult to find the optimal solution.
54.4.2 Exact line search
exactline<-function(x0, grad, tol = 1e-6, max_iteration = 1000){
A = matrix(c(10, 0, 0, 1), ncol = 2)
k = 1
xf = x0
r = matrix(-grad(xf), ncol = 1)
alpha = as.numeric((t(r)%*%r)/(t(r)%*%A%*%r))
xl = xf - alpha * grad(xf)
x = c(x0,xl)
while (sqrt(sum((xl - xf)^2)) > tol && k < max_iteration){
xf = xl
r = matrix(-grad(xf), ncol = 1)
alpha = as.numeric((t(r)%*%r)/(t(r)%*%A%*%r))
xl = xf - alpha * grad(xf)
k = k + 1
x = c(x, xl)
}
return(list(iteration = k - 1,
x1 = x[seq(1, 2 * k - 1, 2)],
x2 = x[seq(2, 2 * k, 2)]))
}
# implement the method
step1 = exactline(c(1.5, -1.5),grad)
z = matrix(0, 100, 100)
x1 = seq(-1.5, 1.5, length = 100)
x2 = seq(-1.5, 1.5, length = 100)
# store function value for every grid point
for(i in 1:100){
for(j in 1:100){
z[i,j] = f(c(x1[i],x2[j]))
}
}
# plot contour map
contour(x1, x2, z, nlevels=20)
for(i in 1:step1$iteration){
segments(step1$x1[i],step1$x2[i],step1$x1[i+1],step1$x2[i+1],lty=2,col='red')
}
Although every step of exact line search is exact, exact line search takes more time compared with others.
54.4.3 Backtracking Line Search
backtracking<-function(x0, grad, tol = 1e-6, alpha = 0.01, beta = 0.8,max_iteration = 1000){
k = 1
xf = x0
xl = xf - alpha * grad(xf)
x = c(x0, xl)
while (sqrt(sum((xl - xf)^2)) > tol && k < max_iteration){
xf = xl
alpha = beta * alpha
xl = xf - alpha * grad(xf)
k = k + 1
x = c(x, xl)
}
return(list(iteration = k - 1,
x1 = x[seq(1, 2 * k - 1, 2)],
x2 = x[seq(2, 2 * k, 2)]))
}
Choose initial \(\alpha = 0.2\), and factor \(\beta = 0.8\)
# implement the method
step1 = backtracking(c(1.5, -1.5), grad, alpha = 0.2, beta = 0.8)
z = matrix(0,100,100)
x1 = seq(-1.5, 1.5, length = 100)
x2 = seq(-1.5, 1.5, length = 100)
# store function value for every grid point
for(i in 1:100){
for(j in 1:100){
z[i,j] = f(c(x1[i], x2[j]))
}
}
# plot contour map
contour(x1, x2, z, nlevels=20)
for(i in 1:step1$iteration){
segments(step1$x1[i],step1$x2[i],step1$x1[i+1],step1$x2[i+1],lty=2,col='red')
}
The large initial \(\alpha\) can be used in backtracking line search, since after several steps \(\alpha\) becomes really small.